→Taylor-expansion is a method of approximating a function f(x) around a point a with a polynomial of the argument x in the vicinity of a. The polynomial itself consists of the derivatives of the function of various orders.

Tn(x) = f(a) + f ‘ (a) (x-a) + f ”(a) (x-a)2/2! +  f(3)(x) (x-a)3/3! + …. + R(x). The Taylor-expansion of the exponential function is:

e<sup>x<\sup> = 1 + x + x2/2 + x3/3! + ……. + xn/n!

To prove the validity of this statement consider the special case of MacLaurin-polynomials were a function is expanded around x=0. Observe the polynomials

p(x) = a +bx + cx2 + dx3

p'(x) = b + 2cx + 3dx2

p”(x) = 2c + 2 *3dx.

x= 0 in each of those equalities and get expressions for the coefficients a,b,c and d. p(0) = a → a=p(0)

p'(0)  = b → b = p'(0)

p”(0) = 2c  → c = p”(0)/2

p(3) (0) = 2•3 d → d= p(3)(0)/ 2•3

Therefore the given polynomial can be written as


p(x) = p(0) + p'(0) x + p”(0)x2 /2+ p(3)(0)/3 !+ …… Xn\n!


Om mattelararen

Licentiate of Philosophy in atomic Physics Master of Science in Physics
Det här inlägget postades i Calculus, Gymnasiematematik(high school math) och har märkts med etiketterna , . Bokmärk permalänken.


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